Binary Search
四点要素:
start + 1 < end,(start和end中间至少有一个数)
start + (end - start) / 2 (不能写成 (start+end)/2, 因为start +end可能会超过int限制)
A[mid] ==, <, > (mid的三种情况)
A[start] A[end] ? target (start和end的判断)
Example:
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*/
// version 1: with jiuzhang template
public class Solution {
/**
* @param A an integer array sorted in ascending order
* @param target an integer
* @return an integer
*/
public int findPosition(int[] nums, int target) {
if (nums == null || nums.length == 0) {
return -1;
}
int start = 0, end = nums.length - 1;
while (start + 1 < end) {
int mid = start + (end - start) / 2;
if (nums[mid] == target) {
return mid;
} else if (nums[mid] < target) {
start = mid;
} else {
end = mid;
}
}
if (nums[start] == target) {
return start;
}
if (nums[end] == target) {
return end;
}
return -1;
}
}
// version 2: without jiuzhang template
public class Solution {
/**
* @param A an integer array sorted in ascending order
* @param target an integer
* @return an integer
*/
public int findPosition(int[] nums, int target) {
if (nums == null || nums.length == 0) {
return -1;
}
int start = 0, end = nums.length - 1;
while (start < end) {
int mid = start + (end - start) / 2;
if (nums[mid] == target) {
return mid;
} else if (nums[mid] < target) {
start = mid + 1;
} else {
end = mid - 1;
}
}
if (nums[start] == target) {
return start;
}
return -1;
}
}